Answer Happy

a) A 0.70 μL sample of an equal volume mixture of 2-pentanone and 1-nitropropane is injected into a gas chromatograph. The densities of these compounds are 0.8124 g/mL for 2-pentanone and 1.0221 g/mL for 1-nitropropane. What mass of each compound was injected? Mass of 2-pentanone 4.0 284 Mass of 1-nitropropane 4.0 357 = mg mg b) The peak areas produced on this injection were 1105 units for 2-pentanone and 918 units for 1-nitropropane. = Calculate the response factor for each compound as area per mg. 2-pentanone: 4478.87 units/mg 1-nitropropane: 4.0 3495.79 X units/mg c) An unknown mixture of these two components produces peak areas of 1767 units (2-pentanone) and 1661 units (1-nitropropane). Use these areas and the response factors above to determine the weight % of the components in the unknown sample. 2-pentanone: 4.0 48.76 1-nitropropane: 4.0 51.23 Submit Answer X % X %