Answer Happy

You have conducted three trials of titration of vinegar with 1.00 M NaOH in three trials. You collected the data shown below. Based on this data, fill out the table in the next question in order to find the molarity of acetic acid. Mass of Vinegar Volume of Vinegar Initial NaOH volume Final NaOH volume Question 9 Trial 1 Volume of NaOH delivered mL Mass of Acetic Acid in Vinegar Molarity of Acetic Acid 4.93 Moles of NaOH delivered mol Moles of Acetic Acid titrated mol B M Trial 1 4.93 g 4.91 ml 8.80 mL 4.60 mL Trial 2 4.86 mL Imol mol M Trial 2 4.87 g 4.86 mL 10.00 mL 5.9 mL Trial 3 5.02 g 5.00 mL 10.00 mL 5.8 mL Trial 3 5.00 mL mol mol M 5 pts