If a solution containing 30.60 g of lead(II) nitrate is allowed to react completely with a solution containing 8.564 g o
Posted: Tue Jul 05, 2022 9:00 am
Question Source McQuarrie, Rock, And Gallogly 4e-General Chemistry Publisher: University Science Books
If a solution containing 30.60 g of lead(II) nitrate is allowed to react completely with a solution containing 8.564 g of sodium sulfate, how many grams of solid precipitate will be formed? mass of solid precipitate: How many grams of the reactant in excess will remain after the reaction? mass of excess reactant: Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (0) for the number of moles. Pb²+ g mol