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mearth = 5.972 · 10²4kg; mmoon = 7.349 · 10²² kg r = 6.67. 10-¹¹ m³/kgs² −11 #1 Come closer, my moon Imagine the moon ge
Posted: Tue Jul 05, 2022 8:54 am
by answerhappygod

- Mearth 5 972 10 4kg Mmoon 7 349 10 Kg R 6 67 10 M Kgs 11 1 Come Closer My Moon Imagine The Moon Ge 1 (218.37 KiB) Viewed 13 times
mearth = 5.972 · 10²4kg; mmoon = 7.349 · 10²² kg r = 6.67. 10-¹¹ m³/kgs² −11 #1 Come closer, my moon Imagine the moon gets very close to the earth up to a distance of 20,000 km (as measured from the centers). The distance from one surface to the other surface therefore would be 20,000 km - moon - rearth = 20,000 km - 6371 km - 1737 km 11892 km. Calculate how long one month would be (the time for the moon's orbit around the earth). On the surface of the moon facing the earth, one has to consider more than the gravitational force of the moon: How large is the centrifugal force due to the moon's orbit? How large is the influence due to the earth gravitational force on that surface of the moon? At which point in between earth and moon do both gravitational forces compensate? How large is the rotational energy of the moon about the earth for such a short distance? =
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