Given: GF= mg = (5.56x10-5 kg)(9.8 m/s2) = 5.48x10-4 or 0.000548 Angle of string: tanθ = 1cm/ 45.5cm or .01m / 0.455m =

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Given:
GF= mg = (5.56x10-5 kg)(9.8 m/s2) = 5.48x10-4 or 0.000548
Angle of string: tanθ = 1cm/ 45.5cm or .01m / 0.455m = θ = 1.26°
Tension (T) = Tcosθ = weight → T × cos (1.26° ) = 0.000548 = T = 5.4813 × 10-4 N
Electric force = T sinθ = 5.4813 × 10-4 × sin(1.26) = 1.21×10-5
r = 0.03m → 0.01m (x1)) + 0.01m (x2) + 0.01m (x3)
trial 1= x= 0.01
trial 2 = x= 0.01
trial 3 = x=0.01
Calculate the distance, r, between the spheres by adding the values of x in each trail . Then, assuming each sphere acquired an equal amount of electric charge, calculate the amount of electric charge on each sphere for each of the three trials