ܙ ، - 159 (power series ) (1 – x?)y" – 2xy' +12 y = 0

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answerhappygod
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ܙ ، - 159 (power series ) (1 – x?)y" – 2xy' +12 y = 0

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ܙ ، - 159 (power series ) (1 – x?)y" – 2xy' +12 y = 0
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