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In the circuit shown below, the current in the diode is given by ip = 1.3 +0.13 sin(wt) mA. The diode has n = 2, Vx = 3.
Posted: Sun Jul 03, 2022 12:10 pm
by answerhappygod
- In The Circuit Shown Below The Current In The Diode Is Given By Ip 1 3 0 13 Sin Wt Ma The Diode Has N 2 Vx 3 1 (61.78 KiB) Viewed 18 times
In the circuit shown below, the current in the diode is given by ip = 1.3 +0.13 sin(wt) mA. The diode has n = 2, Vx = 3.36 V, and Vs = Vm sin(wt). Answer the following two
questions. 2kQ2 iD ww Vs Vx 11. Find the DC component in the diode voltage vp (in V). a) 0.76 b) 0.78 c) 0.80 d) 0.72 + V e) 0.74 12. Find the value of Vm (in mV). Hint: Use small-signal analysis. a) 305 b) 225 c) 245 d) 265 e) 285