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2.7. Two impedances, Z₁ = 0.8+j5.6 N and Z₂ = 8-j16 , and a single-phase motor are connected in parallel across a 200-V

Posted: Sun Jul 03, 2022 12:08 pm
by answerhappygod
2 7 Two Impedances Z 0 8 J5 6 N And Z 8 J16 And A Single Phase Motor Are Connected In Parallel Across A 200 V 1
2 7 Two Impedances Z 0 8 J5 6 N And Z 8 J16 And A Single Phase Motor Are Connected In Parallel Across A 200 V 1 (40.15 KiB) Viewed 22 times
2 7 Two Impedances Z 0 8 J5 6 N And Z 8 J16 And A Single Phase Motor Are Connected In Parallel Across A 200 V 2
2 7 Two Impedances Z 0 8 J5 6 N And Z 8 J16 And A Single Phase Motor Are Connected In Parallel Across A 200 V 2 (40.15 KiB) Viewed 22 times
2 7 Two Impedances Z 0 8 J5 6 N And Z 8 J16 And A Single Phase Motor Are Connected In Parallel Across A 200 V 3
2 7 Two Impedances Z 0 8 J5 6 N And Z 8 J16 And A Single Phase Motor Are Connected In Parallel Across A 200 V 3 (40.15 KiB) Viewed 22 times
power system
2 7 Two Impedances Z 0 8 J5 6 N And Z 8 J16 And A Single Phase Motor Are Connected In Parallel Across A 200 V 4
2 7 Two Impedances Z 0 8 J5 6 N And Z 8 J16 And A Single Phase Motor Are Connected In Parallel Across A 200 V 4 (40.15 KiB) Viewed 22 times
2.7. Two impedances, Z₁ = 0.8+j5.6 N and Z₂ = 8-j16 , and a single-phase motor are connected in parallel across a 200-V rms, 60-Hz supply as shown in Figure 2.23. The motor draws 5 kVA at 0.8 power factor lagging. + I 200/0° V 0.8 j5.6 U₁₂ FIGURE 2.23 Circuit for Problem 2.7. 8 -j16 tla 13 M S3 = 5 KVA at 0.8 PF lag (a) Find the complex powers S₁, S₂ for the two impedances, and S3 for the motor. (b) Determine the total power taken from the supply, the supply current, and the overall power factor. (c) A capacitor is connected in parallel with the loads. Find the kvar and the capacitance in F to improve the overall power factor to unity. What is the new line current?