Answer Happy

Question 1 Not yet answered Marked out of 1.00 Flag question Question 2 Not yet answered Marked out of 1.00 Flag question Question 3 Not yet answered Marked out of 1.00 Flag question Consider the following code: SomeObj o = new SomeObj(); SomeObj o2 = 0.clone(); SomeObj 03 = 0; Modifying o2 will not modify o. Select one: O True O False 03=0 is a shallow copy, so modifying 03 will not modify o. Select one: O True O False Modifying 02 will modify o, since they are sharing the same memory. Select one: O True False