Answer Happy

Q-III: Prokaryotic Lac Operons - Bacteria (Disregard Attenuation) "+"=Wild-Type Z- (Normal Function) | |- = Beta-Gal Mutation (Non-Functional) = Promoter Mutation (No Transcription) | P- = Repressor Mutation (Unable to Bind Operator = Repressor Mutation (Unable to Bind Allolactose) Operator Mutation (Unable to Bind w/ Repressors) Wild-Type = | P+ O+ Z+ (One Copy) A) Would cell transcription be functional if beta-galactosidase protein was present in the cell in low or high lactose levels? Both vs. none? Is P+ 0c Z I* P* O+Z+ B) What if a bacterium has a wild-type / gene, but in its one copy of the lac operon, the operator isn't functional, with low glucose levels, is transcription of the lac operon taking place? POʻz* POZ C) Partial diploid with two copies of the lac operon, assuming glucose levels are low, would there be transcription in the cell in absence/presence of lactose? Is P+ 0c Z I P+ 0+Z+ +