How much heat (in kJ) is needed to evaporate 2.9 moles of CCl4 (liquid) at its standard boiling point of 309 K? ΔS° vap
Posted: Sat Jul 02, 2022 8:44 pm
How much heat (in kJ) is needed to evaporate 2.9 moles of CCl4(liquid) at its standard boiling point of 309 K? ΔS° vap for CCl 4(liquid) = 93.9 J/(mol K).