Hydrogen gas and iodine gas react via the following equation. H₂(g) + I2(g) → 2 HI(g) Ke 79 (at 650 K) = If 0.094 mol HI
Posted: Sat Jul 02, 2022 8:22 pm
Hydrogen gas and iodine gas react via the following equation. H₂(g) + I2(g) → 2 HI(g) Ke 79 (at 650 K) = If 0.094 mol HI is placed in an empty 1.0 L flask at 650 K, what are the equilibrium concentrations of HI, 12, and H₂? [H₂] eq = [1₂ eq [HI] eq = = ΣΣΣ