What quantity in moles of precipitate will be formed when 104.0 mL of 0.350 M NaCl is reacted with excess Pb(NO3)2 in th
Posted: Sat Jul 02, 2022 7:56 pm
What quantity in moles of precipitate will be formed when 104.0 mL of 0.350 M NaCl is reacted with excess Pb(NO3)2 in the following chemical reaction? 2 NaCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 NaNO3(aq)