How much heat (in kJ) is needed to evaporate 1.8 moles of CCl4 (liquid) at its standard boiling point of 393 K? AS° vap
Posted: Sat Jul 02, 2022 7:56 pm
How much heat (in kJ) is needed to evaporate 1.8 moles of CCl4 (liquid) at its standard boiling point of 393 K? AS° vap for CCI 4 (liquid) = 94.0 J/(mol K). Express your answer with ONE decimal place. Type your answer...