Answer Happy

Let's look at another problem Hypothetical problem: Calculate the % of a solute (5 g) removed from 100 mL of toluene after extracting it with 150 mL water (note: K=Ctoluene/Cwater = 0.10)). 0.10= Total amount of solute: 5 g Let "y" the amount that remains in toluene Then 5-y is the amount that will be in water y (g) 100 (mL toluene) 5.0-y (g) 150 (mL water) y = 0.31 g 5.0 g 0.31 g = 4.69 g that went into water. 94 % removed from toluene.