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Posted: **Sat Jul 02, 2022 7:10 pm**

: An Object Is Located 26 Cm To The Left Of A Diverging Lense And The Image Is Located 14 To The Left Of The Same Divergin 1 (11.87 KiB) Viewed 35 times

: An Object Is Located 26 Cm To The Left Of A Diverging Lense And The Image Is Located 14 To The Left Of The Same Divergin 2 (17.37 KiB) Viewed 35 times

An object is located 26 cm to the left of a diverging lense and the image is located 14 to the left of the same diverging lense When the image's height is compared to the object's height, the image's height is O Cannot be determined based on the info O taller O shorter

Question 16 Let a light ray approach a lens with an index of refraction of n-1,59, Calculate the focal length using the radius of curvature for R, to be 10 cm and radius of curvature of R₂ to be-16 cm. What is the focal length of the lens? 10.43 cm -13.25 cm -10.43 cm 13.25 cm 3 pts None of the above