Answer Happy

1. [18/26 Points) DETAILS PREVIOUS ANSWERS Predicting the motion of a planet A star of mass 12 x 1030 kg is located at 8x10¹2, 5 x 10¹2,0 m. A planet of mass 4 x 1024 kg is located at sx 102,9x10¹2, o m and is moving with a velocity of 0.5x 10%, 1.2 x 10,0 m/s. Your task is to predict the motion of the planet in two steps, each of duration 7.0 x 10 seconds. This is a multipart tutorial question. You must get each question correct before you can go on to the next question. In the first time interval the calculations are broken down into their details. In the second time interval you are asked to work more independently, using what you practiced in the first time interval. Part 11 of 14 What is the position of the planet after 7.0 x 107 7 7₁- 0 m. MY NOTES To avoid buildup of small round-off differences, your own answers (after being judged correct within a small tolerance) are used as the basis for later calculations. We will apply the Momentum Principle to the planet as the chosen system, and assume that the only significant interaction with the surroundings is with the stationary star Orient the coordinate axes so that the motion is in the xy plane, with 2-0. Part 1 of 14 What is the relative vector that points from the initial position of the star to the initial position of the planet? 7- -3612✔ -3.00+12 He12 ✔ 4.00 12 0 m PRACTICE ANOTHER Part 2 of 14 What is the magnitude of the relative vector from the star to the planet? 171-5012✔ 5.00+12 m Part 3 of 14 What is the unit vector f that points from the initial position of the star to the initial position of the planet? 2- 00✔ -0.6

Part 4 of 14 What is the magnitude of the gravitational force exerted by the star on the planet? IFI-128620 1.28e+20 N Part 5 of 14 What is the vector gravitational force exerted by the star on the planet? F- 2.68e19✔ 7.68e+19 -1.024620✔ Part 6 of 14 What is the impulse due to the gravitational force during the time interval 7.0 x 107 s? Fat- 5.376627✔ 5.38e+27 -7.168e27✔ -7.17e+27 ON S Part 7 of 14 What is the initial momentum of the planet? P₁- 2e28 ✔ 2.00e+28 4.8625✔ Part 8 of 14 What is the momentum of the planet after 7.0 x 107 s? P₁-2.53862✔ 2.540+28 4.083e28 Part 9 of 14 What is the velocity of the planet after 7.0 x 10 s? 7,- 6345 6350 10207.5✔ -1.02e+200) N Y 4.80e+28,0 kg-m/s 4.08e+28 10200 0 m/s 0 kg-m/s

Part 9 of 14 What is the velocity of the planet after 7.0 x 10 s? Vrm 6345 6350 10207.5✔ 10200 O m/s Part 10 of 14 What is the displacement (change in position) of the planet during the time interval of 7.0 x 10 s? Use the final velocity as an approximation to the average velocity (note that the net from isn't constant), A7- 4.4415ell 4.44e+11 7.14525811✔ 7.15e+11,0 m