(3) The position of the 2 kg object's center of mass is r = 6i + 4j + 2k (m) and its velocity is v = -16i +8j – 12k (m/s
Posted: Fri Jul 01, 2022 7:09 am
(3) The position of the 2 kg object's center of mass is r = 6i + 4j + 2k (m) and its velocity is v = -16i +8j – 12k (m/s). The external forces act on the object is given by ΣF = 2t i + 4j. r (a) What is the object's angular momentum Ho about the origin O at t₂ =1 sec? (b) Determine the angular impulse exerted on the object during interval of time from t₁ =0 to t2 =4s.