1- Interpret the main function using aflowchart.
2- Analyze the subroutine where a string is written intothe LCD.
the following code regulates the speed of the motoraccording to temperature T
T ≥ 75 °C: The motor reaches its maximum forwardspeed.
45 °C ≤ T ≤ 75 °C: Forward speed is raised.
10 °C ≤ T ≤ 45 °C: The motor stops.
0 °C ≤ T ≤ 10 °C: The motor rotates backward.
T ≤ 0 °C: The motor reaches its maximum backwardspeed.
CODE:
#include<reg52.h>#include<stdio.h>#include<lcd1602and18B20.h>
sbit ma=P1^0;sbit mb=P1^1;sbit pwm=P1^2;
uint count;int temp;uchar pwmtemp;
void inittime0();
void main(){pwm=0;pwmtemp=0;init();inittime0();
while(1){if(count==60){count=0;temp=ReadTemperature();temperature=(float)temp*0.0625;sprintf(displaytemp,"Temp % 7.3f",temperature);//´òӡζÈÖµwritestring(1,0,displaytemp);//ÏÔʾµÚ¶þÐÐcommand(0x80+13);write_dat(0xdf);write_dat('C');
if(temperature>75.0){ma=1;mb=0;pwmtemp=75;}if((temperature>45.0)&&(temperature<75.0)){ma=1;mb=0;pwmtemp=temperature;
}if((temperature>10.0)&&(temperature<45.0)){ma=0;mb=0;pwmtemp=0;}if((temperature>0.0)&&(temperature<10.0)){ma=0;mb=1;pwmtemp=temperature*7;}if(temperature<0.0){ma=0;mb=1;pwmtemp=75;}}pwm=1;delay(pwmtemp);pwm=0;delay(75-pwmtemp);
}}/****************ÖжϳÌÐò**********************/void timer0() interrupt 1{TH0=(65536-50000)/256;TL0=(65536-50000)%256;count++;
}void inittime0(){TMOD=0x01;TH0=(65536-50000)/256;TL0=(65536-50000)%256;EA=1;ET0=1;TR0=1;}
- Please Answer 1 And 2 1 Interpret The Main Function Using A Flowchart 2 Analyze The Subroutine Where A String Is Writ 1 (99.11 KiB) Viewed 38 times