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1.05 V+ 9.38 VDD 100k Big 10/2 ~ VT Drain current at saturation and triode : ID = Where KP 2.5 V 1 2KPm 1 ID = KP₁ (VGS
Posted: Fri Jul 01, 2022 6:08 am
by answerhappygod
- 1 05 V 9 38 Vdd 100k Big 10 2 Vt Drain Current At Saturation And Triode Id Where Kp 2 5 V 1 2kpm 1 Id Kp Vgs 1 (333.72 KiB) Viewed 41 times
1.05 V+ 9.38 VDD 100k Big 10/2 ~ VT Drain current at saturation and triode : ID = Where KP 2.5 V 1 2KPm 1 ID = KP₁ (VGS - Vthn)² L W = + Figure 9.38: KPn = 120uA/V² Estimate the AC current, i,, that flows in the test voltage v, (= 1 mV at 1 MHz) in the circuits seen in Fig. 9.53 (and thus what is the small-signal resistance, vli, seen by v?) Use the process data from Table 6.2. Compare your hand calculations to SPICE simulation results. What would happen to the DC biasing of the MOSFET if the capacitor was removed so that the test voltage was connected directly to the drain? Hints: the AC current flowing through the resistor is VT /R while the AC current flowing in the MOSFET is either v/r (for saturation region operation, see Eq. [9.6]) or vr /Rch for triode operation (see Eq. [9.16]). The resistance seen by v, is then the parallel combination of the resistors. VDD - (VGS - VTHN)² 300k Big ir 10/2 KPn = 120uA/V² and VTHN = .8V To 5Mega-ohms VT