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1.1 The circuit in Figure 1.5 has no feature to limit thecurrent drawn via the Darlingtonpair. The current via the Darlington pair must be limited to 2 A.Calculate the value aswell as the wattage of a resistor that is to be inserted in thecollector circuit of theDarlington pair to protect the diode and Darlington pair. Estimatethe ratings of thediode.
1.2 Determine the rms diode current if the diode conducts anaverage of 50 A.
2. Estimate the average load current of a single-phase half-waverectifier fed from a 24V 50 Hz source supplying a resistive load of 1 Ω. Take the diodevolt drop to be 0.8V. 3. A piece-wise-linear model describes a diodes forward volt dropas follows: for the range , where is thediode forward current. Theaverage value of the current via the diode during its ON state is50 A. Determine thediode volt drop during the ON-state.
4. Determine the mean load current in a resistor of 10 Ω fed via asingle diode connectedin series with a 240 V 50 Hz source. The source inductance isnegligible.
5. Determine the peak inverse voltage (PIV) that a diode in asingle-phase half-waverectifier will be subjected to in every cycle if the supply voltageis 240 V 50 Hz.
The voltage source V1 in Figure 1.5 is 17.5 V 50 Hz. Idiode D1n5407 Vs D1 V1 LVload 48 R1 12.5 V2 Q1 Q2 Q2N 3055 BC337 BZX7913V/PS D2 1k R2 din4007 D3 Figure 1.5: Single-phase battery charger / trickle charger