Name: (11) The supply voltage VCC equals 9V. The base resistor RB is 42. Take 0.6V for the knee voltage of the base-emit

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Name 11 The Supply Voltage Vcc Equals 9v The Base Resistor Rb Is 42 Take 0 6v For The Knee Voltage Of The Base Emit 1 (41.27 KiB) Viewed 29 times

Name: (11) The supply voltage VCC equals 9V. The base resistor RB is 42. Take 0.6V for the knee voltage of the base-emitter diode. Draw the load line for a short-circuit current of 15mA (a) What is the value of the collector resistor RC in that case? (b) What is then the voltage Va across the transistor? (c) What is then the current le through the transistor? RB www VCC 9.0V RC Ic (mA) 15 D 10 Student nr. saturation region 5 Answers: (a) RC- (b) Va (c) Ic= active region (12) Same circuit and transistor as above, but now with a short- scircuit current of 5 mA. Draw the new load line. (a) What is the value of the collector resistor RC in that case? (b) What is then the voltage Vc across the transistor? (c) What is then the current Ic through the transistor? cutoff region 10 15 VCE (V) {npn} 20 Answers: (a) RC = (b) VCE= (c) Ic= L₂=0.4 mA 1₁-0.3 mA IB=0.2 mA Ig=0.1mA Ig=0 mA