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IRA# 5 1. Given x(t)= -38(t-1.5) +38(t+1.5) and Fourier transform of x(t) is X(), then X(0) is equal to (a) -1 (b) 0 (c)
Posted: Fri Jul 01, 2022 5:58 am
by answerhappygod
- Ira 5 1 Given X T 38 T 1 5 38 T 1 5 And Fourier Transform Of X T Is X Then X 0 Is Equal To A 1 B 0 C 1 (31.32 KiB) Viewed 49 times
IRA# 5 1. Given x(t)= -38(t-1.5) +38(t+1.5) and Fourier transform of x(t) is X(), then X(0) is equal to (a) -1 (b) 0 (c) 1 (d) 2 (e) 3 Answer: IRA#5_2. Given that the Fourier transform of x(t) is X(o), if x(t) is real and x(t) = -sgn(t), then X(co) is a/an (a) complex-valued function of co with real and imaginary parts (b) real even function of co (c) real odd function of co (d) imaginary even function of co (e) imaginary odd function of co Answer: IRA#5_3. Given that X() is the Fourier transform of x(t) and X() = 2/(1+0²), the amplitude and phase spectra of x(t) are respectively (a) 2, 1+0² (b) 1,2/(1+²) (c) 2/(1+00²), ein/2 (d) 2/(1+0), ez (e) 2/(1+00²), 0 Answer: