Page 1 of 1
Question 3 Not yet answered Marked out of 1.00 P Flag question Consider the operator T:C2C2,x = (x1, x2), y = (1,72), de
Posted: Tue Sep 07, 2021 7:12 am
by answerhappygod
- Question 3 Not Yet Answered Marked Out Of 1 00 P Flag Question Consider The Operator T C2c2 X X1 X2 Y 1 72 De 1 (25.42 KiB) Viewed 87 times
Question 3 Not yet answered Marked out of 1.00 P Flag
question Consider the operator T:C2C2,x = (x1, x2), y = (1,72), defined by T(x) = (x1 + ix2, x1 – ix2). Then the adjoint of T is Tüy = Select one: O 1 + y2, yz - iyi) O : + y2, ily2 - y2)) none (1 + y2, (y1 - y2)) O Vi + y2, Y1 - y2)