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Posted: **Thu Jun 30, 2022 6:20 pm**

: 4 A Chemistry 1411 Student Mixed 25 Grams Of Fe With 40 Grams Of H O The Balanced Equation For This Reaction Is An 95 1 (21.75 KiB) Viewed 85 times

: 4 A Chemistry 1411 Student Mixed 25 Grams Of Fe With 40 Grams Of H O The Balanced Equation For This Reaction Is An 95 2 (21.75 KiB) Viewed 85 times

4. A chemistry 1411 student mixed 25 grams of Fe with 40 grams of H₂O. The balanced equation for this reaction is An 95% yield of Fe3O4 was obtained. a) 3Fe(s) + 4H₂O(1) Fe3O4(s) + H2(g) b) What is the theoretical yield of Fe3O4? What is the limiting reactant in this experiment? grams (5 points) (2 points) What is the actual yield of Fe3O4 if the reaction gave a 95% yield? grams (3 points)
a) E 5. Lead (II) bromide is prepared using the following reaction: Pb(NO)(aq) + KBr(aq) PbBr(s) + KNO(aq) (unbalanced) (2 points) How many milliliters of 2.25 M Lead(11) nitrate (Pb(NO3):) are needed to prepare 275 grams of PbBr; in excess potassium bromide solution. Assume you have 100% yield. a) Fill in the stoichiometric flowchart below with the information from this problem. (3 points) b) Show the dimensional analysis calculation needed (5 points)