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You used 11.2 g of glyceryl tripalmitate (MW = 807.32 g/mol) and 62.4 mL of a 5.0 M NaOH (MW = 40.0 g/mol) solution fo t
Posted: Thu Jun 30, 2022 6:11 pm
by answerhappygod
- You Used 11 2 G Of Glyceryl Tripalmitate Mw 807 32 G Mol And 62 4 Ml Of A 5 0 M Naoh Mw 40 0 G Mol Solution Fo T 1 (49.54 KiB) Viewed 42 times
You used 11.2 g of glyceryl tripalmitate (MW = 807.32 g/mol) and 62.4 mL of a 5.0 M NaOH (MW = 40.0 g/mol) solution fo the synthesis of soap (MW= 256.4 g/mol). O H₂C-O(CH2)14-CH3 HC-o- HC-o O (CH2)—CH3 + 3 NaOH (CH2)-CH3 Glyceryl Tripalmitate 3 O c. 3.59 g O d. 10.77 g OO Na O (CH₂) 14CH3 Sodium Palmitate (soap) What is the theoretical yield of sodium palmitate? O a. 3.0 mols O b. 1.0 mol + H₂C-OH H₂C-OH H₂C-OHA Glycerol