3. The perpendicular distance between two parallel tangents of a reverse curve is 35 m. The azimuth of the back tangent
Posted: Tue Sep 07, 2021 7:08 am
- 3 The Perpendicular Distance Between Two Parallel Tangents Of A Reverse Curve Is 35 M The Azimuth Of The Back Tangent 1 (54.92 KiB) Viewed 479 times
completely and neatly so i can read it and i swear to you ill give
you a thumbs up if did answer the 2 problems. thanks advance
engineer.
3. The perpendicular distance between two parallel tangents of a reverse curve is 35 m. The azimuth of the back tangent of the curve is 270° and the azimuth of the common tangent is 300°. If the radius of the back curve is 150 m and the stationing of PRC is 10 + 140, find the stationing of PT. Use the arc basis. 4. It is proposed to introduce a reverse curve between two straights AB and CD intersecting at a point I with ZCBI = 30° and ZBCI = 120°. The reverse curve consists of two circular arcs AX and XD, X lying on the common tangent BC. If BC = 791.71, the radius Rax = 750 m, and the stationing of B is 1 + 250, calculate the following: a. The radius RxD b. The lengths of the reverse curve. c. The stationing of D.