The Fourier series for f(t) = 0 -2

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answerhappygod
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The Fourier series for f(t) = 0 -2

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The Fourier Series For F T 0 2 T 1 T 1 T 1 Is Given By 0 1 T 2 F T 4 F T All T 4 Sin In 2 Sin 124 1
The Fourier Series For F T 0 2 T 1 T 1 T 1 Is Given By 0 1 T 2 F T 4 F T All T 4 Sin In 2 Sin 124 1 (98.79 KiB) Viewed 107 times
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The Fourier series for f(t) = 0 -2 <t<-1 t, -1<t <1 is given by 0 1<t<2 f(t + 4) = f(t), all t 4 sin(in/2) + sin ( 124). 2n2 -2 cos(in/2) S(t) = 7n = • Use Dirichlet theorem to determine S(1) = (decimal). · Substitute t = 1 and use the identity 2 sin(a) cos(a) = sin(2a) to determine such A so that sin (an/2) AS(1) (decimal). En 2n2 • The complex Fourier series for f(t) can be written as f(t) einnt/2. Determine co = Cnet (integer) and ic2 = (round to the third decimal place). • What can you say about c_2020? Choose one of the following options: A: C_2020 = -C2020,B: C-2020 = C2020, C: c_2020 = C1010, D: C_2020 = (C2020)*. Type the corresponding capital letter A cos(in/2) • Parseval's identity can be written as į S 2, f(t)2 dt = n- + 8 sin? (m/2) (in) Give the 2n=1 2n2 values of A= (integer) and B= (integer). . Use Parseval's identity to evaluate nel 8 sinº (in/2) A cos(in/2) + ?n? = (round to (in) the third decimal place).
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