line left 48.00 Question 7 Not yet answered Marked out of 4,00 The partial fractions for solving the initial value probl

[answerhappygod]

Line Left 48 00 Question 7 Not Yet Answered Marked Out Of 4 00 The Partial Fractions For Solving The Initial Value Probl 1 (27.15 KiB) Viewed 72 times

line left 48.00 Question 7 Not yet answered Marked out of 4,00 The partial fractions for solving the initial value problem by the Laplace transform for this equation is dy dY + 2 dY 3Y = 6e dt dr with Y(0) = 2 and -(0)-14 dr P Flag question 2(-2)? -6(-2)-14 (-2+3)(2+1) 2(-3)? -6(-3) -14 BE (-3+ 2X-3-1) 2-6-14 -18 се (1 + 2)(1+3) 12 6 = 2 3 22 11 4 2 3 2 None of the choices 2(-2) - 6(-2) - 14 6 -2 (-2+3X-2-1) - 2-3)- 6(-3) -14 22 (-3.+ 2X-3-1) 4 2-6-14 -1823 (1 + 2X1 + 3) 12 2