Answer Happy

Data and Calculations, Part 1: Mass of porcelain evaporating dish: 44.65. Mass of porcelain evaporating dish and steel wool 5.96 Mass of steel wool 1.31 45.9644.65=1.31 5 5 46.52-04.65=187 Mass of porcelain evaporating dish and product (iron oxide): Mass of product (iron oxide): 4652 1.87 1.) Calculate the moles of iron in your sample of steel wool, assuming it is made from 100% iron: mass 1.31 = 0.0235 molar mass 2.) Calculate the grams of oxygen in your product: 55.859 1,87-1.31 -0.569 3.) Calculate the moles of oxygen in your product: 0.56 us =0.012 4.) Determine the empirical formula of your iron oxide: Fe 0.0235 0.012 0.012 0.012 1.95²2 Fe₂O
Data and Calculations, Part 2: Before Heating Mass of porcelain evaporating dish: 66.75 69.04-66.75=2.29 Mass of porcelain evaporating dish plus hydrated copper (I) sulfate: 69.048 Mass of hydrated copper (II) sulfate: 2.29 69.04-662 +0.83 68.21-66.75=1.46 After Heating Mass of evaporating dish plus anhydrous copper (u) sulfate: 68.21, Mass of anhydrous copper (11) sulfate: 1.46 Mass of water that was vaporized/lost from your sample": 0.838 "This represents the original mass of water that was part of your sample for the next equation! 9.) Determine the mass percent of water in your sample of copper (II) sulfate hydrate: Mass of water Mass Percent of water = Mass of hydrate (100) 0.83g x 10 = 36.24% . 2.299 10.) Determine the number of waters of hydration in your sample of copper (W) sulfate hydrate: moles of water Number of waters of hydration moles of anhydrous compound 0.03163 = 3,475.0024 0.0091 -0.03163 0.57 18.02 Rounded to the nearest whole number. 4 1.46 = 0.0001 159.61