T Given 1 f(x) = x4 – 23 - sin (73) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolation to solve questi
Posted: Tue Sep 07, 2021 7:06 am
- T Given 1 F X X4 23 Sin 73 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To Solve Questi 1 (61.99 KiB) Viewed 70 times
- T Given 1 F X X4 23 Sin 73 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To Solve Questi 2 (30.78 KiB) Viewed 70 times
- T Given 1 F X X4 23 Sin 73 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To Solve Questi 3 (33.11 KiB) Viewed 70 times
- T Given 1 F X X4 23 Sin 73 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To Solve Questi 4 (33.41 KiB) Viewed 70 times
- T Given 1 F X X4 23 Sin 73 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To Solve Questi 5 (31.55 KiB) Viewed 70 times
Given 1 f(x) = x* – 23 – –sin (1x) defined over the interval [0, 6] where h=1. Use N.G.F. 3 - I sin Starting from (x=3), d3P3(x)/dx3 at x=3 using central derivative is:
Given 1 f(x) = x+ – 23 – – sin (TX) defined over the interval [0, 6] where h=1. Use N.G.F. - I a Starting from (x=1), dP4(x)/dx at X=1 is:
Given 1 sin (1) TT defined over the interval [0, 6] where h=1. Use N.G.F. f (x) = x4 – 23 = – – Starting from x=3; d2P3(x)/dx? at x=3 is: 68 None 88 102
Given f (x) = x4 – x3y – I sin (13) defined over the interval [0, 6] where h=1. Use N.G.F. Starting from x=2; The absolute error (dP2(x)/dx - df(x)/dx| at x=3 is: 17 14 10 None