13 In the following diagram. ABC is a triangle in which is the midpoint of BC, and is a point on AC such that AE: EC = 2
Posted: Tue Sep 07, 2021 7:06 am
13 In the following diagram. ABC is a triangle in which is the midpoint of BC, and is a point on AC such that AE: EC = 2:1 (see bottom of page for HINT] 10A = 2.03 - and OC = $. find: (a) ( 0B C 131 @ DE (3) (W) DE 121 Анти Ag - 28-09 - =
(b) () Find BA + CA + 2B0 [2] (1) Hence deduce that BA + CA + 2BC is parallel to DE.
(b) () Find BA + CA + 2B0 [2] (1) Hence deduce that BA + CA + 2BC is parallel to DE.