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13 In the following diagram. ABC is a triangle in which is the midpoint of BC, and is a point on AC such that AE: EC = 2

Posted: Tue Sep 07, 2021 7:06 am
by answerhappygod
13 In The Following Diagram Abc Is A Triangle In Which Is The Midpoint Of Bc And Is A Point On Ac Such That Ae Ec 2 1
13 In The Following Diagram Abc Is A Triangle In Which Is The Midpoint Of Bc And Is A Point On Ac Such That Ae Ec 2 1 (22.67 KiB) Viewed 82 times
13 In The Following Diagram Abc Is A Triangle In Which Is The Midpoint Of Bc And Is A Point On Ac Such That Ae Ec 2 2
13 In The Following Diagram Abc Is A Triangle In Which Is The Midpoint Of Bc And Is A Point On Ac Such That Ae Ec 2 2 (10.47 KiB) Viewed 82 times
13 In the following diagram. ABC is a triangle in which is the midpoint of BC, and is a point on AC such that AE: EC = 2:1 (see bottom of page for HINT] 10A = 2.03 - and OC = $. find: (a) ( 0B C 131 @ DE (3) (W) DE 121 Анти Ag - 28-09 - =
(b) () Find BA + CA + 2B0 [2] (1) Hence deduce that BA + CA + 2BC is parallel to DE.