Answer Happy

Open with Experiment The Motion of an Object in One Dimension objective of this experimentale describe the motion of an object in free full; describe average velocity, instantaneous velocity, and the differences between them; and, • determine the acceleration of a falling object Learning Outcomes Upon completion, you will be able to • describe the average velocity as it relates to objects in motion • describe instantaneous velocity as it relates to objects in motion. • explain the difference between the average velocity and instantaneous velocity of a moving object. • determine the average velocity of an object accelerated at a constant rate from rest. determine the instantaneous velocity at specific times given a set of everage velocities at timed intervals corresponding to an object's motion determine the acceleration of an object from a graph of distance traveled vs clapred time squared determine the acceleration of an object from a graph of instantaneous velocity vs clapsed Required Equipment • Ticker tape • Ticker tape timer . Ruler . time . Assorted masses PocketLab Onc Module (Optional) Phone/computer (optional) caplain the effect of friction on the motion of

Procedure Report the experiment as many times as possible until you data matches your expectations of the results » Constant velocity 1. Cut a piece of the ticker tape, two (2) meters in length 2. Attach the ticker tape to the given glider. 3. Align the other end of the tape through the ticker tape timer. 4. Place the glider at the end closest to the ticker timer as shown in figure 4.1a (left image) and give the glider a gentle push away from the timer so that it takes about 2 seconds to reach the other end of the air track 5. Turn the timer on in the 40 Hz setting immediately after pushing and allow the tape to pass through the timer undisturbed 6. When the tape has stopped moving, turn off the time and retrieve the tape. Ensuro marked dots are visible so that analysis can be carried out » Constant acceleration 1. Once more, cut a piece of the ticker tape, two (2) meters in length 2. Align the ticker tape through the ticker tape timer as shown in figure 4.1b (right image). 3. Attach the given mass to the other end of the ticker tape, by placing the hook in a pierced hole at the end of the tape. 4. Locate the 40Hz switch for the ticker tape timer, then when ready turn on the ticker tape timer machine while simultaneously releasing the tape $. Once all the tape is through the titer, turn off the time and retrieve the tape. Ensure marked dots are visible so that analysis can be carried out » Data collection Repeat the section below for both tapes 1. Mark your intervals on the ticker tape by drawing a line through the first dot, and every dot thereafter. The time interval is

Lab 4 - Mo Interval ovoon- 8 9 10 11 12 13 14 15 16 17 18 19 20 Table 1: Distance traveled in each inte Distance (m) Avg Velocity (m) 0.003 0.120 0.003 0.120 0.004 0.100 0.013 0.520 0.022 0.880 0.028 1.120 0.035 1.400 0.042 1.880 0.048 1.920 0.052 2.080 0.058 2.320 0.003 2.520 0.069 2.700 0.074 2.960 0.070 3.180 0.084 3.380 0.091 3.640 0.008 3,840 0.103 4.120 0.108 4.320

Interval 1 2 3 2h IN 5 G 7 51asprQub化TH2 8 9 10 11 12 13 14 Table 2: Total distance and total time at the end of each in z (m) time (s) time squared (s' 0.003 0.025 0.000625 0.006 0.050 0.002500 0.010 0.075 0.005625 0.023 0.100 0.010000 0.045 0.125 0.015625 0.073 0.150 0.022500 0.108 0.175 0.030625 0.150 0.200 0.040000 0.198 0.225 0.050825 0.250 0.250 0.082500 0.308 0.275 0.075625 0.371 0.300 0.000000 0.440 0.325 0.105825 0.514 0.350 0.122500 0.593 0.375 0.140625 0.877 0.400 0.180000 0.788 0.425 0.180825 0.884 0.450 0.202500 0.987 0.475 0.225825 1.075 0.500 0.250000 17 18 19 20

Interval 一 3 5 6 7 8 9 10 11 12 13 14 Tag==仪它ubbHp作业 Table 3: Instantaneous velo v (m/s) time (s) 0.120 0.0125 0.120 0.0375 0.180 0.0825 0.520 0.0875 0.880 0.1125 1.120 0.1375 0 0.1025 1.880 0.1875 1.020 0.2125 2080 0.2375 2320 [ 2.520 0.2875 2760 0.3125 2.980 0.3375 3.180 0.3825 3.300 0.3875 3.840 0.4125 0.4375 4.120 0.4825 4.320 0.4875 15 16 17 3.840 18 19 20

Velocty vs Time for object as it falls 5.000 4.500 y = 0.2499x - 0.1625 4.000 3.500 3.000 2.500 2.000 1.500 1.000 0.500 0.5 0.4 0.000 0.3 0.1 0.2 Time (s) -0.600