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I tried this problem many different ways. I'm not sure why it's wrong. I'm not sure why. if someone could explain that would be great. please use the same symbols I use and write out instructions in print. Thank you.
ourse Home HW6 No. 10 10 of 10 > Review | Constants 1 Two tiny spheres of mass 5.30 mg carry charges of equal magnitude, 72.0 nC, but opposite sign. They are tied to the same ceiling hook by light strings of length 0.530 m. When a horizontal uniform electric field E that is directed to the left is turned on, the spheres hang at rest with the angle 0 between the strings equal to 58.0° . L L E

PHY 242-11 Course Home SHW6 No. 10 < 10 of 10 > E Part A Which ball (the one on the right or the one on the left) has positive charge? the one on the right the one on the left Submit Previous Answers ✓ Correct Part B

HW6 No. 10 < 10 of 10 > E Part A Which ball (the one on the right or the one on the left) has positive charge? the one on the right the one on the left Submit Previous Answers ✓ Correct Part B What is the magnitude E of the field?

5.30ng & 1000poon #10 - S. × a 72 x 10-9 29 -- % Qc + Tcoso-mg = 0

Tcoso - mq=0 Ted Tsino 2 - Fq - FE=0 T Fa + Tsino Toso = ng F I sino - Fq t FE Img Y Tsino = q + FE 7 T Coso= mg Eq+FE tano ng + ng tano Fq + Fe + tan o 4 Fq 8 E ng

Tsino = Fg + FE Tcoso= mg Eq +FE tano ng Fq у ng tano = Fg + Fe tan o Fq ng E q E Fq E S. 3 x s. 3 *10- s.rx 1210-9 9,8 73x10 E s. 1940s mg tano - E =