Page 1 of 1

Question 15 1 pts Given / (*) = - x - sin (ra) defined over the interval (0,6] where h=1. Use N.G.F. Interpolation to so

Posted: Tue Sep 07, 2021 7:02 am
by answerhappygod
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 1
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 1 (24.38 KiB) Viewed 68 times
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 2
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 2 (18.58 KiB) Viewed 68 times
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 3
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 3 (17.55 KiB) Viewed 68 times
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 4
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 4 (25.84 KiB) Viewed 68 times
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 5
Question 15 1 Pts Given X Sin Ra Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To So 5 (21.41 KiB) Viewed 68 times
Question 15 1 pts Given / (*) = - x - sin (ra) defined over the interval (0,6] where h=1. Use N.G.F. Interpolation to solve questions (15 to 19). The maximum order of the polynomial that we get from the data is:

Question 16 1 pts Starting from (x-2), d4P4(x)/dx4 at x-2 using central derivative is:

Question 17 2 pts Starting from (x-1), dP4(x)/dx atx=1 is:

Question 18 2 pts Starting from x=2; The absolute error (dP2(x)/dx - df(x)/dxl at x=4 is: O 25 None 27 O 23

Question 19 1 pts Starting from x=3;dP3(x)/dx? atx=3 is: 102 O 88 O None 68