Question 15 1 pts Given f (x) = 7* – 2 sin (1x) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolation to

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Question 15 1 pts Given f (x) = 7* – 2 sin (1x) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolation to

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Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 1
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 1 (27.59 KiB) Viewed 64 times
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 2
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 2 (22.46 KiB) Viewed 64 times
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 3
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 3 (12.79 KiB) Viewed 64 times
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 4
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 4 (25.57 KiB) Viewed 64 times
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 5
Question 15 1 Pts Given F X 7 2 Sin 1x Defined Over The Interval 0 6 Where H 1 Use N G F Interpolation To 5 (25.28 KiB) Viewed 64 times
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Question 15 1 pts Given f (x) = 7* – 2 sin (1x) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolation to solve questions (15 to 19). 7T * The maximum order of the polynomial that we get from the data is:

Question 16 1 pts Starting from (x=3), dP3(x)/dx3 at x=3 using central derivative is:

Question 17 2 pts dP4(x)/dx at x=0 is:

Question 18 2 pts Starting from x=2; The absolute error (DP2(x)/dx-df(x)/dxl at x=4 is: None 25 27 23

Question 19 1 pts Starting from x=3; d2P3(x)/dx? at x=3 is: None 88 68 102
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