T Given f (x) = x4 – 23 - sin (7x) defined over the interval [O, 6] where h=1. Use Divided Difference Interpolation to s

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T Given f (x) = x4 – 23 - sin (7x) defined over the interval [O, 6] where h=1. Use Divided Difference Interpolation to s

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T Given F X X4 23 Sin 7x Defined Over The Interval O 6 Where H 1 Use Divided Difference Interpolation To S 1
T Given F X X4 23 Sin 7x Defined Over The Interval O 6 Where H 1 Use Divided Difference Interpolation To S 1 (46.76 KiB) Viewed 65 times
T Given F X X4 23 Sin 7x Defined Over The Interval O 6 Where H 1 Use Divided Difference Interpolation To S 2
T Given F X X4 23 Sin 7x Defined Over The Interval O 6 Where H 1 Use Divided Difference Interpolation To S 2 (12.69 KiB) Viewed 65 times
T Given F X X4 23 Sin 7x Defined Over The Interval O 6 Where H 1 Use Divided Difference Interpolation To S 3
T Given F X X4 23 Sin 7x Defined Over The Interval O 6 Where H 1 Use Divided Difference Interpolation To S 3 (18.58 KiB) Viewed 65 times
T Given F X X4 23 Sin 7x Defined Over The Interval O 6 Where H 1 Use Divided Difference Interpolation To S 4
T Given F X X4 23 Sin 7x Defined Over The Interval O 6 Where H 1 Use Divided Difference Interpolation To S 4 (23.77 KiB) Viewed 65 times
T Given f (x) = x4 – 23 - sin (7x) defined over the interval [O, 6] where h=1. Use Divided Difference Interpolation to solve questions (11 to 14). The number of 2nd order Poly. functions that we can get from the data is:

Starting from (x=2), the absolute error |P2(0) - f(0)| is:

Starting from x=3; dP2(x)/dx at x=1 is: 0-347 0-147 0-287 O None

Starting from x=4; The absolute error (dP1(x)/dx - df(x)/dx/ at x=4 is: None O 101 O 104 O 107
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