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T Given f(x) = x4 – 23 - sin (12) defined over the interval [O, 6] where h=1. Use N.G.F. Interpolation to solve question

Posted: Tue Sep 07, 2021 7:01 am
by answerhappygod
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 1
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 1 (43.84 KiB) Viewed 80 times
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 2
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 2 (18.42 KiB) Viewed 80 times
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 3
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 3 (10.61 KiB) Viewed 80 times
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 4
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 4 (15.48 KiB) Viewed 80 times
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 5
T Given F X X4 23 Sin 12 Defined Over The Interval O 6 Where H 1 Use N G F Interpolation To Solve Question 5 (18.02 KiB) Viewed 80 times
T Given f(x) = x4 – 23 - sin (12) defined over the interval [O, 6] where h=1. Use N.G.F. Interpolation to solve questions (15 to 19). * The maximum order of the polynomial that we get from the data is:

Starting from (x=3), d3P3(x)/dx3 at x=3 using central derivative is:

Starting from (x=1), dP4(x)/dx at x=1 is:

Starting from x=2; The absolute error |dP2(x)/dx - df(x)/dx| at x=4 is:

Starting from x=3; d2P3(x)/dx2 at x=3 is: 88 O 102 68 O None