- Question 1 2 Pts T Given 1 F X X4 23 Sin 713 Defined Over The Interval 0 6 Use Integration Methods To Solve 1 (42.7 KiB) Viewed 63 times
- Question 1 2 Pts T Given 1 F X X4 23 Sin 713 Defined Over The Interval 0 6 Use Integration Methods To Solve 2 (24.08 KiB) Viewed 63 times
- Question 1 2 Pts T Given 1 F X X4 23 Sin 713 Defined Over The Interval 0 6 Use Integration Methods To Solve 3 (30.32 KiB) Viewed 63 times
- Question 1 2 Pts T Given 1 F X X4 23 Sin 713 Defined Over The Interval 0 6 Use Integration Methods To Solve 4 (38.43 KiB) Viewed 63 times
- Question 1 2 Pts T Given 1 F X X4 23 Sin 713 Defined Over The Interval 0 6 Use Integration Methods To Solve 5 (37.38 KiB) Viewed 63 times
Question 1 2 pts T Given 1 f (x) = x4 – 23 sin (713) defined over the interval [0, 6]. Use integration methods to solve questions (1 to 5). Using a step size h = 2 for the interval [0,6], the area underf (x) between [2,6] using Trapezoidal Rule is:
Question 2 2 pts Using three area segments, the estimated area under f(x) between [0,6] using Simpson's 1/3 Rule is:
Question 3 2 pts Using three data points between (0, f (0)), (4,f (4)) including these two data points, the estimated area under f(x) between [0,6] using Simpson's 3/8 is:
Question 4 2 pts If the interval [0, 6] was divided into 4 points including (0, f (0)), (6,f (6)), the estimated area under f (x) between [0,6] using Simpson's 1/3 is then Trapezoidal: 1756.3 O 1421.3 579.3 None
Question 5 2 pts If the interval [1, 4] was divided into 7 points including (0, f (0)), (4,f(4)), the x-value of the sixth point in the evenly spaced data starting from the point (0,f (0)) is: 02.5 None 3 O 4.5