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Weight of 20 tablets = 7.5g ml of 0.5M HCL(sample) = 19.1 ml of 0.5M HCL(blank) = 30.1 Molecular weight= 180.0 Content p

Posted: Fri Mar 04, 2022 10:29 am
by answerhappygod
Weight Of 20 Tablets 7 5g Ml Of 0 5m Hcl Sample 19 1 Ml Of 0 5m Hcl Blank 30 1 Molecular Weight 180 0 Content P 1
Weight Of 20 Tablets 7 5g Ml Of 0 5m Hcl Sample 19 1 Ml Of 0 5m Hcl Blank 30 1 Molecular Weight 180 0 Content P 1 (28.71 KiB) Viewed 37 times
Weight Of 20 Tablets 7 5g Ml Of 0 5m Hcl Sample 19 1 Ml Of 0 5m Hcl Blank 30 1 Molecular Weight 180 0 Content P 2
Weight Of 20 Tablets 7 5g Ml Of 0 5m Hcl Sample 19 1 Ml Of 0 5m Hcl Blank 30 1 Molecular Weight 180 0 Content P 2 (39.43 KiB) Viewed 37 times
Weight Of 20 Tablets 7 5g Ml Of 0 5m Hcl Sample 19 1 Ml Of 0 5m Hcl Blank 30 1 Molecular Weight 180 0 Content P 3
Weight Of 20 Tablets 7 5g Ml Of 0 5m Hcl Sample 19 1 Ml Of 0 5m Hcl Blank 30 1 Molecular Weight 180 0 Content P 3 (39.43 KiB) Viewed 37 times
Weight Of 20 Tablets 7 5g Ml Of 0 5m Hcl Sample 19 1 Ml Of 0 5m Hcl Blank 30 1 Molecular Weight 180 0 Content P 4
Weight Of 20 Tablets 7 5g Ml Of 0 5m Hcl Sample 19 1 Ml Of 0 5m Hcl Blank 30 1 Molecular Weight 180 0 Content P 4 (39.43 KiB) Viewed 37 times
Weight of 20 tablets = 7.5g ml of 0.5M HCL(sample) = 19.1 ml of 0.5M HCL(blank) = 30.1 Molecular weight= 180.0 Content per tablet = 300mg Take weight of powder containing 0.5 g aspirin g Using the data above calculate the content % and content per tablet
Acid-base titrations for basic and acidic og drugs .Calculations depend on stoichometry of the reactions and strength (molarity , normality ) of titrants e.g. analysis of aspirin with NaOH ěš” OC-CH3 OH + CH3COONa COONa + 2 NaOH o COOH