Answer Happy

The solution of (1 + y2)dx = (tan- y - x)dy is (a) (W) = tan-' - 1+ ce-tan- (b) x(y) = tan-?y + ce-tan-ly (c) x(y) = tan-ly-1+ ceta (d) y(x) = tan-20-1+cetan-, (e) y(x) = tan-+x+ce tan d (a) (b) O (c) 0 (d) (e)