a=4 b=6 c=6 d=5 use the 2nd photo as a basis in answering
Posted: Fri Mar 04, 2022 9:53 am
a=4 b=6 c=6 d=5
use the 2nd photo as a basis in answering
Problem 3 (15pts): A soil element is shown in the figure. Determine the (a) maximum principal stress, and the (b) normal and (c) shear stresses on plane AB. 5a psf 2c psf + B 4bo1 f tid -lad psf 2c psf A +
a. Maximum Stress, 01: (Eq. 2.20) Oytox 01 + Txy? 2 2 2 0; =970 +679+ + 2 2 128 kPa + 162 kPa 128 kPa - 162 kPa 01 + + (32 kPa)2 = 181.235 kPa 2 2 Minimum Stress, 03: (Eq. 2.22) 162 kPa) = 2 Oy - 03 byt ox + 2 2 les Or) + Txy? 2 2 2 03 128 kPa + 162 kPa 2 128 kPa - 162 kPa 2 kPa) + (32 kPa)2 = 108.765 kPa = + b. Normal Stress along AB, on: (Eq. 2.6) Oy + 0x Oy - Ox on + cos20 + Tyysin 20 2 2 128 kPa + 162 kPa 128 kPa - 162 kPa On + -cos70 + (32 kPa)sin 70 2 2 On = 169.256 kPa - = - Shear Stress along AB, Tn: (Eq. 2.12) Oy - Ox 128 kPa - 162 kPa sin20 – Txycos20 sin 70 - (32 kPa)cos 70 2 2 Tn = -26.919 kPa en = In
use the 2nd photo as a basis in answering
- A 4 B 6 C 6 D 5 Use The 2nd Photo As A Basis In Answering 1 (27.98 KiB) Viewed 34 times
- A 4 B 6 C 6 D 5 Use The 2nd Photo As A Basis In Answering 2 (79.18 KiB) Viewed 34 times
a. Maximum Stress, 01: (Eq. 2.20) Oytox 01 + Txy? 2 2 2 0; =970 +679+ + 2 2 128 kPa + 162 kPa 128 kPa - 162 kPa 01 + + (32 kPa)2 = 181.235 kPa 2 2 Minimum Stress, 03: (Eq. 2.22) 162 kPa) = 2 Oy - 03 byt ox + 2 2 les Or) + Txy? 2 2 2 03 128 kPa + 162 kPa 2 128 kPa - 162 kPa 2 kPa) + (32 kPa)2 = 108.765 kPa = + b. Normal Stress along AB, on: (Eq. 2.6) Oy + 0x Oy - Ox on + cos20 + Tyysin 20 2 2 128 kPa + 162 kPa 128 kPa - 162 kPa On + -cos70 + (32 kPa)sin 70 2 2 On = 169.256 kPa - = - Shear Stress along AB, Tn: (Eq. 2.12) Oy - Ox 128 kPa - 162 kPa sin20 – Txycos20 sin 70 - (32 kPa)cos 70 2 2 Tn = -26.919 kPa en = In