Answer Happy

Posted: **Sat Feb 26, 2022 11:59 am**

: Consider The Reaction Shown Below X Ha Aq H20 1 2a Aq H30 Aq Kf 8 20 10 5 M What Is The Value Of The Equil 1 (31.7 KiB) Viewed 46 times

Consider the reaction shown below: X HA (aq) + H20 (1) 2A (aq) + H30+ (aq) Kf=8.20 10-5 M What is the value of the equilibrium constant for the reverse reaction, K,? OK,= +8.20 x 10-5 O K = -8.20 x 10-5 O K = +8.20 x 105 OK, = +1.22 x 10-10 O K = +1.22 x 104