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Posted: **Sat Feb 26, 2022 11:59 am**

: Phosphoric Acid H Po1 Reacts With Potassium Hydroxide Koh According To The Following Equation H3po4 3 Kohk3po4 3 1 (48.84 KiB) Viewed 47 times

: Phosphoric Acid H Po1 Reacts With Potassium Hydroxide Koh According To The Following Equation H3po4 3 Kohk3po4 3 2 (29.97 KiB) Viewed 47 times

Phosphoric acid (H, PO1) reacts with potassium hydroxide (KOH) according to the following equation H3PO4 +3 KOHK3PO4 + 3 H2O Consider the case of 150 ml of 0.3 M potassium hydroxide reacting with 120 ml of 0.5 M phosphoric acid when answering the following questions. D Question 1 2 pts What is the limiting reagent in the reaction? Potassium Hydroxide Phosphoric Acid Question 2 3 pts How many moles of water will be produced during the reaction?

Question 3 3 pts How many moles of potassium phosphate (K3PO4) will be produced in the reaction? Question 4 3 pts What mass of potassium phosphate (K;PO) will be produced in the reaction?