Compute for the amount (in grams) of Sodium bicarbonate that reacted with 5.6 grams of tartaric acid. 2NaHCO3 (84g/mol)
Posted: Sat Feb 26, 2022 11:56 am
Compute for the amount (in grams) of Sodium bicarbonate that
reacted with 5.6 grams of tartaric acid.
2NaHCO3 (84g/mol) + C4H6O6
(150g/n) -> 2HO2 + 2CO2 +
Na2C4H4O6
reacted with 5.6 grams of tartaric acid.
2NaHCO3 (84g/mol) + C4H6O6
(150g/n) -> 2HO2 + 2CO2 +
Na2C4H4O6