Page 1 of 1
III - (4 pts) (will be introduced on Monday) The switch in the circuit below was neutral, and then was set in position a
Posted: Sat Feb 26, 2022 11:50 am
by answerhappygod
- Iii 4 Pts Will Be Introduced On Monday The Switch In The Circuit Below Was Neutral And Then Was Set In Position A 1 (49.25 KiB) Viewed 88 times
- Iii 4 Pts Will Be Introduced On Monday The Switch In The Circuit Below Was Neutral And Then Was Set In Position A 2 (49.25 KiB) Viewed 88 times
III - (4 pts) (will be introduced on Monday) The switch in the circuit below was neutral, and then was set in position a for 0.3 seconds. Suddenly it is switched to position b for 0.5 s, then back to a. Over that 0.5s lapse of time, how much energy was dissipated by the 2nd resistor? Suggested steps: 1 - Find the charge in the capacitor at t = 0.3 seconds, using the charging function of a capacitor of capacitance C by a battery of voltage : Q(t) = Qmax(1 - e!), with Qmax = CÉ›. 2- That value of Q(t = 0.3 sec) becomes the Qo for the function of the capacitor discharge. 3 - To find the total energy dissipated AE integrate (t) R over time as seen in class. 1200 12 WW a b E = 60 V C=100 uF 5500 12 W I