Answer Happy

EX1-4) Given the ideal system as shown: X,(1) y) y(1) y (1) prefilter HRE) x(t) sampler 2(t) AVD DSP Hospf) D/A Half postfilter HOST) f, clock The Hpre(f) and Hpost(f) are 3rd order analog lowpass filters with cutoff frequencies of 4 KHz. The sample rate, fs, is 20 KHz. The DSP is implementing passthrough (y(t) = ĉ(t) ] at 20 KHz. Components described below are sinusoidal. True/false: EX1-4a) TF EX1-4b) An 8 KHz component of xat) will be attenuated approximately 12dB by HpRE(f): A 40 KHz noise tone in y(t) will be attenuated approximately 60dB by Hpost(f): An 8 KHz component of y(t) will be aliased by Hpost(f): TF EX1-4c) T EX1-4d) An 18 KHz component of x(t) will be both attenuated and aliased within f(t): TF EX1-4e) A 12 KHz even component of x(t) will constructively interfere in c(t) with an 8 KHz even component of x(t): TF EX1-4f) A 16 KHz component of xa(t) will be attenuated by 36dB within x(t): T F EX1-4g) A 60 KHz component of xalt) will be aliased to DC within i(t): TF EX1-4h) The attenuation of Hpost(h) is approximately 18dB/decade: TF EX1-41) TF Hpost(f) will attenuate the 20 KHz sampling noise in y(t) by more than 36dB: Equal magnitude 16 KHz and 24 KHz odd components of xa(t) would completely cancel each other in i(t): EX1-4) TF