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Posted: **Sat Feb 26, 2022 11:46 am**

: Viny Ision With Equal Masses Data Table 1 Table 1a Cart A Before Collision Cart A Mass M Distance D M Time 1 1 (46.48 KiB) Viewed 48 times

: Viny Ision With Equal Masses Data Table 1 Table 1a Cart A Before Collision Cart A Mass M Distance D M Time 1 2 (44.44 KiB) Viewed 48 times

: Viny Ision With Equal Masses Data Table 1 Table 1a Cart A Before Collision Cart A Mass M Distance D M Time 1 3 (17.64 KiB) Viewed 48 times

viny .. ision with Equal Masses Data Table 1 Table 1A. Cart A before collision. Cart A mass, m Distance, d (m) Time, 1 (s) (kg) .0672 kg .5 m Trial 1:.62 Trial 2: .55 Trial 3: .60 Average time, t Velocity =d/t (m/s) VA .59 s .84 Table 1B. Cart A after collision. Cart A mass, m Distance, d (m) Time, 1 (5) (kg) .0672 kg 1:10 Trial 1:.63 Trial 2: .59 Trial 3:.62 Average time, t Velocity -d/t (m/s) VA 675 116 Table 1C. Cart B after collision. Cart B mass, m Distance, d (m) Time, t(s) (kg) _0676 .5 m Trial 1:.77 Trial 2: .78 Trial 3: .86 Average time, t Velocity =d/t (s) (m/s) vel 90S 182
Calculations for Activity 1. Elastic Collision with Equal Masses Apply the law of conservation of momentum to the two cart system by calculating the momentum before and after the collision. Helpful equations: Momentum before the collision = MAVA + Mgvo Momentum after the collision = mvA' + mavs MAVA + mov= MAVA' + mavs' first value - second value Percent difference = first value + second value 2 < 100% 1. Calculate the momentum of the system before the collision (the left side of the equation) and after the collision (the right side of the equation). Before 1.0672*.84+0)=.056 After (.0672.16)+1.0676*.62)=.052
2. Calculate the percent difference between the two values. .056-.052 100%=7.4% .056+.052 2 3. Explain any difference in the values before and after the collision.