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Lemma: If an E Q is Cauchy and qn does not maps to 0, then there exist 8 and N so that |9n| > S for n > N
Theorem 1.9.
Posted: Sat Feb 26, 2022 11:00 am
by answerhappygod

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Lemma: If an E Q is Cauchy and qn does not maps to 0, then there exist 8 and N so that |9n| > S for n > N
Theorem 1.9. If an E Q is Cauchy and qn does not maps to 0, then it is Cauchy.
Hint:lan = 9m-an = |qm||an Чт