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Find the Inverse Laplace Transform of (s +1) X(S) (52 +8 – 1) = e = (a) x(t) -.5t (cos(.866t) +.577 sin(.866t)) u(t) (b)
Posted: Sat Feb 26, 2022 10:56 am
by answerhappygod
- Find The Inverse Laplace Transform Of S 1 X S 52 8 1 E A X T 5t Cos 866t 577 Sin 866t U T B 1 (81.18 KiB) Viewed 36 times
Find the Inverse Laplace Transform of (s +1) X(S) (52 +8 – 1) = e = (a) x(t) -.5t (cos(.866t) +.577 sin(.866t)) u(t) (b) r(t) = (.618e-1.618 x) = +1.618.618t) u(t) (C) x(t) = (.276e-1.618 +.724e-618t) u(t) (d) x(t) = .5t (.577 cos(.866t) + sin(.866t)) u(t) (e) none of the above = =e